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For a reversible reactionn at 298 K the ...

For a reversible reactionn at 298 K the equilibrium constant K is 200. What is value of `DeltaG^(@)` at 298 K ?

A

`-13.13kcal`

B

`-0.13kcal`

C

`-3.158kcal`

D

`-0.413kcal`

Text Solution

Verified by Experts

The correct Answer is:
C
Applying `DeltaG^(@)=-2.303RTxxlogK`
`" "=-2.303xx2xx298xxlog200`
`" "=-3158.4" cal "=-3.158" kcal"`
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