A solution of `HCI` has p`H = 5`. If `1mL` of it is diluted to `1L` what will be the `pH` of resulting solution?

Options

A. 3.45
B. 6.96
C. 8.58
D. 10.25

Answer

B

Explanation

`pH=5,[H^(+)]=10^(-5)M`
After dilution `=(10^(-5))/(1000)=10^(-8)M`
Total `[H^(+)]=10^(-8)+10^(-7)=1.1xx10^(-7)`
`pH=-log[H^(+)]=-log(1.1xx10^(-7))=6.96`