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Equimoler solulition of HF, HCOOH and HC...

Equimoler solulition of HF, HCOOH and HCN at 298 K have the values of Ka as `6.8xx10^(-4), 1.8xx10^(-4)` and `4.8xx10^(-9)` respectively, what will be the order of their acidic strength ?

A

`HFgtHCNgtHCOOH`

B

`HFgtHCOOHgtHCN`

C

`HCNgtHFgtHCOOH`

D

`HCOOHgtHCNgtHF`

Text Solution

Verified by Experts

The correct Answer is:
B
Acidic strength `prop sqrt(K_(a))`
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