Dissociation constant of `CH_(3)COOH` and ` NH_(4)OH` in squeous solution are `10^(-5)` if pH of a `CH_(3)COOH` solution is 3, what will be the pH of `NH_(4)OH` ?

Options

A. `3.0`
B. `4.0`
C. `10.0`
D. `11.0`

Answer

D

Explanation

`"pH of "CH_(3)COOH=3`
`[H^(+)]=10^(-3)"M from"CH_(3)COOH`
`[NH_(4)OH]=[CH_(3)COOH]=10^(-3)M`
`[OH^(-)]=10^(-3)M`
`[H^(+)][OH^(-)]=10^(-14)`
`[H^(+)]=(10^(-14))/(10^(-3))=10^(-11)`
`"pH of "NH_(4)OH=-log(10^(11))=11`