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solubility product of radium sulphate is...

solubility product of radium sulphate is `4xx10^(-9)`. What will be the solubility of ` Ra^(2+)` in ` 0.10 M` ` NaSO_(4)`?

A

`xx10^(-10)M`

B

`2xx10^(-5)M`

C

`4xx10^(-5)M`

D

`2xx10^(-10)M`

Text Solution

Verified by Experts

The correct Answer is:
A
`RaSO_(4)hArrRa^(2+)+SO_(4)^(2-)`
`K_(sp)=[Ra^(2+)][SO_(4)^(2-)]`
Concentration of `SO_(4)^(2-)` from `Na_(2)SO_(4)=0.10M`
`Ra^(2+)=(4xx10^(-11))/(0.10)=4xx10^(-10)`
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