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What will be the solubility of AgCl in 0...

What will be the solubility of AgCl in 0.05 M NaCl aqueous solution if solubility product of AgCl is `1.5xx10^(-10)` ?

A

`3xx10^(-9)" mol L"^(-1)`

B

`0.05" mol L"^(-1)`

C

`1.5xx10^(-5)" mol L"^(-1)`

D

`3xx10^(9)" mol L"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(sp)=[Ag^(+)][Cl^(-)]`
`[Cl^(-)]=NaCl=0.05M`
`Ag^(+)=(1.5xx10^(10))/(0.05)=3xx10^(-9)M`
`[Ag^(+)]=` solubility `=3xx10^(-9)M`
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