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Calculate pH at which Mg(OH)(2) begins t...

Calculate pH at which `Mg(OH)_(2)` begins to precipitate from a solution containing `0.10M Mg^(2+)` ions. `(K_(SP)of Mg(OH)_(2)=1xx10^(-11))`

A

4

B

6

C

9

D

7

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(sp)" for "Mg(OH)_(2)=1.0xx10^(-11)`
`[Mg^(2+)][OH^(-)]^(2)=(0.1)xx10[OH^(-)]^(2)=1.0xx10^(-11)`
`[OH^(-)]^(2)=(1xx10^(-11))/(0.1)=10^(-10)`
`[OH^(-)]=10^(-5),[H^(+)]=(10^(-14))/(10^(-5))=10^(-9)`
`pH=9`
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