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A solution which is 10^(-3)M each in Mn^...

A solution which is `10^(-3)M` each in `Mn^(2+), Fe^(2+), Zn^(2+)`, and `Hg^(2+)` it treated with `10^(-16)M` sulphide ion. If the `K_(sp)` of `MnS, FeS, ZnS`and `HgS` are `10^(-15), 10^(-23), 10^(-20)`,and `10^(-54)`, respectively, which one will precipitate first?

A

FeS

B

MnS

C

HgS

D

ZnS

Text Solution

Verified by Experts

The correct Answer is:
C
`M^(2+)+S^(2-)toMS`
Lower the value of `K_(sp)`, lower will be solubility. Hence, HgS will precipitate first.
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