`N_(2)O_(4) hArr 2NO_(2), K_(c)=4`. This reversible reaction is studied graphically as shown in the figure. Select the correct statement out of `I, II` and `III`.
I : Reaction quotient has maximum value at point `A`
II : Reaction proceeds left to right at a point when `[N_(2)O_(2)]=[NO_(2)]=0.1 M`
III : `K=Q` when point `D` or `F` is reached:

Options

A. I,II
B. II,III
C. I,III
D. I,II,III

Answer

B

Explanation

`I.Q=([NO_(2)]^(2))/([N_(2)O_(4)])`
Since, `[NO_(2)]` is minimum and `[N_(2)O_(4)]` is maximum at point A, hence Q is minimum at this point. Thus, false
`II.Q=((0.1)^(2))/((0.1))=0.1ltK_(c)`
Thus, reaction proceeds left to right. Thus, true.
III. `K_(c)=Q` when equilibrium is reached is reached at point D or F. Thus, true.