At 500 K, equlibrium constant, `K_(c)` for the following reaction is 5.
`1//2 H_(2)(g)+ 1//2(g)hArr HI (g)`
What would be the equilibrium constant `K_(c)` for the reaction `2hi(g)hArrH_(2)(g)+l_(2)(g)`

Options

A. 0.04
B. 0.4
C. 25
D. 2.5

Answer

A

Explanation

`(a)/(2)H_(2(g))+(1)/(2)I_(2(g))hArrHI_((g)),K_(c)=5` . . . (i)
Multiply eqn (i) by 2,
`H_(2(g))+I_(2(g))hArr2HI_((g)),(K_(c))=(5)^(2)` . . . (ii)
Now, recerse the reaction
`2HI_((g))hArrH_(2(g))+I_(2(g)),K_(c)=(1)/((5)^(2))`
`:.K_(c)=(1)/(25)=0.04`