Oxidation number if iodine in `IO_(3)^(-), IO_(4)^(-),KI and I_(2)` respectively are

Options

A. `-2, -5, -1, 0`
B. `+5, +7, -1, 0`
C. `+2, +5, +1, 0`
D. `-1, +1, 0, +1`

Answer

B

Explanation

`IO_(3)^(-)rarr x+3(-2)=-1rArr x=+5`
`IO_(4)^(-)x+4(-2)=-1 rArr x = +7`
`KI rarr +1+x=0 rArr x = - 1`
`I_(2)rarr0 rArr x=0`