Carbon is in the lowest oxidation state in

Options

A. `CH_(4)`
B. `C Cl_(4)`
C. `CF_(4)`
D. `CO_(2)`

Answer

A

Explanation

Oxidation number of carbon in the given compound:
In `overset(x+1)(CH_(3))=x+4(+1)=0 " " rArr x=-4`
In `overset(x) C overset(-1)(Cl_(4))=x+4(-1)=0 " " rArr x=+4`
In `overset(x)C overset(-1)F_(4)=x+4(-1)=0 " " rArr x=+4`
In `overset(x) C overset(-2)O_(2)=x+2(-2)=0 " " rArr x= +4`