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When KMnO(4) is reduced with oxalic acid...

When `KMnO_(4)` is reduced with oxalic acid in acidic solution, the oxidation number of `Mn` changes from

A

`+2` to `+7`

B

`+4` to `+7`

C

`+7` to `+2`

D

`+6` to `+2`

Text Solution

Verified by Experts

The correct Answer is:
C
`2overset(+7)MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)rarr 2 overset(+2)Mn^(2+)+10CO_(2)+8H_(2)O`
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On reduction of KMnO_(4) by oxalic acid in acidic medium, the oxidation number of Mn. What is the magnitude of is change?

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