The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions is

Options

A. `1//3`
B. `1//6`
C. `2//3`
D. `3//4`

Answer

A

Explanation

`Cr_(2)O_(7)^(2-)+3Sn^(2+)+14H^(+)rarr 2 Cr^(3+)+3Sn^(4+)+7H_(2)O`
1 mole of `Sn^(2+)` will reduce `1/3` moles of `K_(2)Cr_(2)O_(7)`.