the pair of lines having equation `3x^2 -2xy-2y^2=0` has one line as incident ray and other as reflected ray then equation formed by its mirror lines

If the pair of lines x^2+2xy+ay^2=0 and ax^2+2xy+y^2=0 have exactly one line in common, then the joint equation of the other two lines is given by

If two pairs of straight lines having equations y^(2)+xy-12x^(2)=0 and ax^(2)+2hxy+by^(2)=0 have one line common, then a =

A ray of light travelling along the line 2x-3y+5=0 ,after striking a plane mirror lying along the line x+y-2=0 gets reflected then equation of the reflected straight line is

If the pairs of lines x^(2)+2xy+ay^(2)=0andax^(2)+2xy+y^(2)=0 have exactly one line in common then the joint equation of the other two lines is given by

If the pairs of lines x^(2)+2xy+ay^(2)=0andax^(2)+2xy+y^(2)=0 have exactly one line in common then the joint equation of the other two lines is given by

If the pairs of lines x^(2)+2xy+ay^(2)=0andax^(2)+2xy+y^(2)=0 have exactly one line in common then the joint equation of the other two lines is given by

If the pairs of lines x^(2)+2xy+ay^(2)=0 and ax^(2)+2xy+y^(2)=0 have exactly one line in common,then the joint equation of the other two lines is given by 3x^(2)+8xy-3y^(2)=03x^(2)+10xy+3y^(2)=0y^(2)+2xy-3x^(2)=0x^(2)+2xy-3y^(2)=0

A ray of light is sent along the line x-2y-3=0 on reaching the line 3x-2y-5=0 the ray is reflected from it, then the equation of the line containing the reflected ray is

A ray of light is sent along the line x-2y-3=0 upon reaching the line 3x-2y-5=0, the ray is reflected from it. Find the equation of the line containing the reflected ray.

A ray of light is sent along the line x-2y-3=0 upon reaching the line 3x-2y-5=0, the ray is reflected from it. Find the equation of the line containing the reflected ray.