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bar a=a1 bari + a2bar j+a3 bar k, where ...

`bar a=a_1 bari + a_2bar j+a_3 bar k`, where `a_1, a_2, a_3` are rational numbers. If `bara` makes an angle `45^@` with the vector `beta=sqrt2 i+3sqrt2 j+4bar k and |baralpha|` is rational, then `|alpha|` lies in

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