A helicopter, moving vertically upwards, releases a packet when it is a certain height the ground. The packet initially moves upwards for a time `t_(1)` and then falls dowanwards for a time `t_(2)` until it reaches the ground. Then

A ball is thrown vertically upward with a speed v from a height h above the ground . The time taken for the ball to hit the ground is

A balloon is going upwards with a velocity of 20 m It releases a packet when it is at a height of 160 m from the ground. The time taken by the packet to reach the ground is

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A body is projected vertically upwards from the ground. On reaching the greatest height

If a helicopter is moving upwards with acceleration g and food packet are thrown from a height h . Find time period to reach those packet to ground

A balloon is going upwards with velocity 12 m//sec it releases a packet when it is at a height of 65 m from the ground. How much time the packet will take to reach the ground (g=10 m//sec^(2))

A balloon is going upwards with velocity 12 m//sec it releases a packet when it is at a height of 65 m from the ground. How much time the packet will take to reach the ground (g=10 m//sec^(2))

A particle is projected vertically upwards from a point O on the ground. It takes time t_(1) to reach a point A at a height h above the ground, it continues to move and takes a time t_(2) to reach the ground. Find (a) h, (b) the maximum height reached and (c ) the velocity of the partical at the half of maximum height.