A box contains 30 tickets, bearing only one number from 1 to 30 on each. If one ticket is drawn at random, find the probability of an event that the ticket drawn bears

Answer

A, B

Explanation

The box contains 30 tickets
`thereforeS={1,2,3,....,30}`
`thereforen(S)=30.`
(1) Let A be the event that the ticket drawn is an odd number.
`Then A={1,3,5,7,9,11,13,15,17,19,21,23,25,27,29}`
`thereforen(A)=15.`
`P(A)=(n(A))/(n(S))=(15)/(30)=(1)/(2)`
(2) Let B the event that the ticket drawn bears a complete square number.
`ThenB={1,4,9,16,25}`
`thereforen(B)=5.`
`P(B)=(n(B))/(n(S))=(5)/(30)=(1)/(6).`