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There are six cards in a box, each beari...

There are six cards in a box, each bearing a number from 0 to 5. Find the probability of each of the following events, that a card drawn shows,

A

(1) a natural number.

B

(2) a number less than 1.

C

(3) a whole number.

D

(4) a number greater than 5.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
The number on the cards are from 0 to 0.5
`thereforeS={0,1,2,3,4,5}." "thereforen(S)=6`
(1) Let A be the event that the card drawn shows a natural number.
`Then A={1,2,3,4,5}" "thereforen(A)=5`
`P(A)=(n(A))/(n(S))=(5)/(6)`
Let B be the event that the card drawn shows a number less than 1.
`ThenB={0}." "thereforen(B)=1`
`P(B)=(n(B))/(n(S))=(1)/(6).`
Let C be the event that the card drawn shows a whole number.
`Then C={0,1,2,3,4,5}." "thereforen(C)=6`
`P(C)=(n(C))/(n(S))=(6)/(6)=1.`
Let D be the event that the card drawn shows a number greater than 5.
`ThenD={ }." "thereforen(D)=0`
`P(D)=(n(D))/(n(S))=(0)/(6)=0.`
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