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In DeltaABC, ray BD bisects /ABC. A-D-C,...

In `DeltaABC`, ray `BD` bisects `/_ABC`. `A-D-C`, side `DE||` side `BC`, `A-E-B`.
Prove that, `(AB)/(BC)=(AE)/(EB)`.
Complete the activity by filling the boxes.

In `DeltaABC`, ray `BD` is the bisector of `/_ABC`
`:.(AB)/(BC)=square`.......`(I)` (By angle bisector theorem)
In `DeltaABC`, seg `DE||` side `BC`
`:.(AE)/(EB)=(AD)/(DC)`........`(II)` `square`
`:.(AB)/(square)=(square)/(EB)`.......[From `(I)` and `(II)`]

Text Solution

Verified by Experts

`(AD)/(DC), By Basic proportionality theorem , (AB)/(BC)=(AE)/(EB)`
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-BOARD'S QUESTION PAPER -QUESTION
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