If `f:R->R` and `g:R->R` defined by `f(x)=2x+3` and `g(x)=x^2+7` then the values of `x` for which `f(g(x))=25` are

If f:R rarrR and g:R rarrR are defined by f(x)=2x+3, g(x)=x^(2)+7 then the value of x for which f[g(x)]=25 are

If f:R to R and g:R to R are defined by f(x)=(2x+3) and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

If f: R to R and g: R to R are defined by f(x)=2x+3 and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

Let R be the set of real numbers and the functions f:R rarr R and g:R rarr R be defined by f(x)=x^(2)+2x-3 and g(x)=x+1 Then the value of x for which f(g(x))=g(f(x)) is

If f : R to R and g:R to R are defined by f(x)=2x+3 and g(x)=x^(2)+7 , then the values of x such that (gof)(x)=8 are -

If f: (R) rarr (R) and g (R) rarr (R) defined by f(x)=2x+3 and g(x)=x^(2)+7 ,then the values of x such that g(f(x))=8 are

If f:R rarr R and g : R rarr R are defined by f(x) = 3x + 2 and g(x) = x^2 - 3 , then the value of x such that g(f(x))=4 are

If f:R -> R, g:R -> R defined as f(x) = sin x and g(x) = x^2 , then find the value of (gof)(x) and (fog)(x) and also prove that gof != fog .