The function `f: R -> R, g: R -> R` are defined as follows: `f(x) = { 0 (x is rational), 1 (x is irrational), g(x) = { -1, (x is rational), 0, (x is irrational)` Then `(fog) (pi) + (gof) (e) =`

Two functions f:Rrarr R, g:R rarr R are defined as follows : f(x)={{:(0,"(x rational)"),(1,"(x irrational)"):}," " g(x)={{:(-1,"(x rational)"),(0,"(x irrational)"):} then (fog)(pi)+(gof)(e)=

Two functions f:Rrarr R, g:R rarr R are defined as follows : f(x)={{:(0,"(x rational)"),(1,"(x irrational)"):}," " g(x)={{:(-1,"(x rational)"),(0,"(x irrational)"):} then (fog)(pi)+(gof)(e)=

Two functions f:RtoR and g:RtoR are defined as follows: f(x)={(0,(x"rational")),(1,(x "irrational")):} g(x)={(-1,(x"rational")),(0,(x "irrational")):} then (gof)( e )+(fog) ( pi ) =

Two functions f:RtoR and g:RtoR are defined as follows: f(x)={(0,(x"rational")),(1,(x "irrational")):} g(x)={(-1,(x"rational")),(0,(x "irrational")):} then (gof)( e )+(fog) ( pi ) =

f(x)={(x", if x is rational"),(0", if x is irrational"):}, g(x)={(0", if x is rational"),(x", if x is irrational"):} Then, f-g is

Two mappings f:R to R and g:R to R are defined as follows: f(x)={(0,"when x is rational"),(1,"when x is irrational"):} and g(x)={(-1,"wnen x is rational"),(0,"when x is irrational"):} then the value of [(gof)(e)+(fog)(pi)] is -

Two mappings f:R to R and g:R to R are defined as follows: f(x)={(0,"when x is rational"),(1,"when x is irrational"):} and g(x)={(-1,"wnen x is rational"),(0,"when x is irrational"):} then the value of [(gof)(e)+(fog)(pi)] is -

Two functions f: R rarr R and g: R rarr R are defined by f(x) = {(0,x \ rational)(1 , x \ irrational),:}g(x)={(-1,x \ rational)(0 , x \irrational):} then g of e + fog(pi)

The functions RR,g:R R are defined as f(x)={0, whenxis rational and 1 when x is irrational } and g(x)={-1 when x is rational and 0 when x~ is~ irrational}~ find~ fog (pi) and gof(e)