If the functions of `f` and `g` are defined by `f(x)=3x-4` and `g(x)=2+3x` then `g^(-1)(f^(-1)(5))`

If f:R rarr and g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x then (g^(-1)" of"^(-1))(5)=

If f:R rarr R,g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x ,then (g^(-1) of^(-1))(5)=

If f:R rarr R and g:R rarr R are define by f(x)=3x-4 and g(x)=2+3x , then (g^(-1)of^(-1))(5)=

If the functions of f and g are defined by f(x) = 3x-4, g(x) = 2+3x for x in R respectively, then g^(-1)(f^(-1)(5))=

let the functions f: RR rarr RR and g: RR rarr RR be defined by f(x)=3x+5 and g(x)=x^(2)-3x+2 . Find (i)(g o f) (x^(2)-1), (ii) (f o g )(x+2)

If f(x)=3x+1 and g(x)=x^(3)+2 then ((f+g)/(f*g))(0) is:

If f and g are real functions defined by f(x) =2x-1 and g(x) =x^(2) , then prove that (3f-2g)(1)=1

Function and g defined on RrarrR" as "f(x)=x^2+7 and g(x)=3x+5. Then f(3) + g(-5) = ….. .