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Find the sum of money if the difference between compound interest and simple interest for 3 years becomes Rs. 930 at the rate of 10% per annnum.

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Let the sum of money be Rs.x.
`:.` At the rate of 10% compound interest per annum.
the amount of Rs. x for years `=Rs.x(1+10/100)^(3)`
`=Rs. X(1+1/10)^(3)=Rs. x xx(11/10)^(3)`
`=Rs. (1331x)/1000`
`:.` Compound interest `=Rs. ((1331x)/1000-x)=Rs. (1331x-1000x)/1000`
`=Rs. (331x)/1000`
Again at the rate of 10% interest per annum, the simple interest of Rs.x for 3 years.
`=Rs.(x xx10x3)/100=Rs.(30x)/100`
As per question `(331x)/1000-(30x)/100=930`
`implies(331x-300x)/1000=930` ltrbgt `implies31x=930xx1000`
`impliesx=(930xx1000)/31=30000`
`:.` The required sum of money `=Rs. 30000`.
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