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If the simple interest of a certain sum of money for 1 year is Rs. 50 and compound interest for 2 years is Rs. 102, then find the sum of money and the rate of interest.

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Let the principal be Rs. `x` and the rate of interest be r% per annum.
`:.` at the rate of r% interest per annum, the
simple interest of 1 year `=Rs. (x xxr xx1)/100=Rs. (rx)/100`
As per question `(rx)/100=50impliesrx=5000`…………..1
Again at the rate of r% compound interest per annum of Rs. x in 2 years,
the amount `=Rs. x xx(1+r/100)^(2)`
`:.` The compound interest `=Rs.{x xx(1+r/1-100)^(2)-x}`
`=Rx[(1+r/100)^(2)-1]`
`=Rs. x[(1+r/100+1)(1+r/100-1)]`
`=Rs. x[(2+r/100)xxr/100]`
`=Rs. (xr)/100(2+r/100)`
`Rs. 5000/100(2+r/100)` [by 1]
`=Rs. 50(2+r/100)=Rs. (100+r/2)`
As per question `100+r/2=102-100impliesr/2=2impliesr=4`
`:.` From 1 we get `4x=5000[ :'r=4]`
`impliesx=5000/rimpliesx=1250`
`:.` The required sum of money `=Rs. 1250` and rate of interest `=4%` per annum.
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