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The length of tow chords AB and CD o...

The length of tow chords AB and CD of the circle with centre at O are equal . If `angle AOB = 60^(@)` , then the value of `angle COD` is .

A

`40^(@)`

B

`30^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
We know that equal chords of a circle subtend equal angles at the centre , `therefore ` the cords AB and CD also subtend equal angles at the f centre.
`therefore angle AOB = angle COD or , 60^(@) = angle COD`
Hence `angle COD = 60^(@) rArr` (c) is correct .
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