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Write with proof which of the chords...

Write with proof which of the chords passing through any point in a circle will be the least .

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Infinite number of chords can be drawn through a point in a circle . Among them the chord of which the line segment obtained by joining the centre and the internal point is a perpendicular bisector will be the least in length . Because we know that so far as the pependicular distance of the chords from the centre increases, the lenght of the chord proportionately diminishes and among the chords which can be drawn through this point , the perpendicular distance form the centre of that chords will be the greatest, i.e., the perpendicular distance of that chord from the centre will be the greatest .
Hence the lenght of that very chord will be the leat .
Mathematically let p be any point in the cirlce with centre at O. Let us join O, P let us drawn a line segment CD such that CD is perpendicular to OP at P and which intersects the circle at C and D. Then CD is a chords passing thorough P . Let AB be another chord passing though P.
we have to prove that the chord CD is smaller .
Construction : Let us draw ` OQ bot AB`
Proof ` angle OQP =1` right angle `[because OQ bot AB]`
In `Delta OPQ gt angle OPQ rArr OP gt OQ`
[ `because` the side opposite to greater angle is greater that the side opposite to smaller angle ] . i.e., the perpendicular distance of the chord CD form the centre O is greater that of the chord AB.
So, the chord CD is at a greater distance than that of AB from the centre .
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