Home
Class 10
MATHS
AB and CD are two chords of a circle wi...

AB and CD are two chords of a circle with centre at O , the ratio of lengths of which is 4: 5. If the perpendicular distance of AB from O be d cm, then perpendicular distance of CD from O.

Text Solution

Verified by Experts

The correct Answer is:
`sqrt(d^(2) - (9k^(2))/(4)) , k` = proportional constant
Promotional Banner

Topper's Solved these Questions

  • THEOREMS RELATED TO CIRCLE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE - 1 (Long - answer type question )|9 Videos

  • THEOREMS RELATED TO CIRCLE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE - 1 (Fill in the blanks. )|3 Videos

  • SPHERE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE|36 Videos

  • THEOREMS RELATED TO CYCLIC QUADRILATERAL

    CALCUTTA BOOK HOUSE|Exercise Long -answer type questions (L.A.)|12 Videos

Similar Questions

Explore conceptually related problems

AB and CD are two equal chords of a circle with centre at O. If the distacne of AB form O be 2 cm , then find the distance of CD form O.

PQ and RS are two chords of equal length of a circle with centre O. If the perpendicular distance from O upon PQ is 9cm, then distance of RS from O is

AB and AC are two such chords of the circle with centre at O that each is perpendicular..., r to the other. If AB=4 cm and AC=3 cm, then find the radiu of the circle.

AD and AC are two equal chords of a circle with centre O. AB is the diameter of the circle. If angleCOD =140^@ , then angleOBC =

AB and CD are two chords of equal lengths of the circle with centre at O. The distance of the chord AB from the centre O is 4cm. Then the distance of the chords CD from the centre O is

AB and CD are two chords of equal length of the cirlc e with centre at O. The distance of the chord AB form the centre Ois 4 cm. Then the distance of chord CD form the center O is

The radius of a circle with O as the centre is 10cm. The length of the chord PQ is 16cm. What is the length of the perpendicular drawn from O on PQ.

AB is a chord of a circle with centre at O and radius 13 cm in length If AB = 10cm then find the distance from centre to the chord.

In the isosceles DeltaABC , AB = AC , O is any point on the side BC. OP and OQ are the perpendicular distance of the sides AB and AC from O respectively. BD is the perpendicular distance of AC from B. Show that OP + OQ = BD.