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If the quadrilateral ABCD circumscribed about the circle , then prove that `AB+ CD= BC+ DA.`

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The quadrilateral ABCD is circumsribed about a circle. Prove that AB+ CD= BC+DA.

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CALCUTTA BOOK HOUSE-THEOREMS RELATED TO TANGENT IN A CIRCLE -EXERCISE 4.2
  1. The centre of a circle with radius of 6 cm is O. The length of the tan...

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  2. If the radius of a circle be zero, then the circle is called a point ...

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  3. Only three tangents can be drawn from a external point of a circle.

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  4. The tangent to a circle and the radius passing through the point of co...

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  5. The number of direct common tangents to two intersecting circles is ""

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  6. The straight line PAB intersects the circle with centre O at the point...

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  7. Two circles touch each other internally. The radius of the larger circ...

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  8. Two circles touch each other externally. The distance between two cent...

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  9. The radius of a circle with centre O is 5 cm. The length of the tangen...

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  10. AB is a diameter of the circle with centre O. The tangent, drawn at a ...

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  11. Prove that form any external point two tangents can be drawn to circle...

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  12. Two tangents are drawn from an external point A of the circle with cen...

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  13. Prove that the internal bisector of the angle between two tangents dra...

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  14. Prove that the internal angle between two tangents drawn from an exter...

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  15. The incircle of Delta ABC touches the sides AB, BC and CA of the trian...

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  16. If the quadrilateral ABCD circumscribed about the circle , then prove ...

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  17. Puja has drawn a circle wit centre of O of which AB is a diameter. Two...

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  18. Laxmi has drawn two circles which intersect each other at O externally...

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  19. Length of radius of two circles are 5cm and 3cm . If two circles touch...

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  20. The radii of two circles are R and r unit (R gtr). If the distance bet...

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