The price of a diamond is ₹ 2000. The di...

The price of a diamond is ₹ 2000. The diamond is broken into two pieses of equal weights. If the price of a diamond varies as the square of its weight, then find the amount of loss for the breakage.

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₹ 1000

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The price of a diamond is rs 2000 . The diamond is broken into to equal weights . If the price of a diamond varies as the square of its weights , then find the amound of loss for the breakage.

A piece of diamond is broken into three pieces, the weights of the pieces being in the ratio 1: 2:3 . Price of a piece of diamond is proportional to the square of its weight . Find the price of the original piece , if the loss due to breakage is rs 22000 .

A valuable piece of stone whose price is rs 15600 breaks into three pieces whose weights are in the ratio 2:3:5 . If the value of the stone varies as the cube of its weights , find the percentage of loss due to breaking .

The value of diamond varies as the square of its weight . A diamond broke into three pieces whose weights are in the ratio 3:4:5 . For this there is a loss rs 9400. Find the value of the original diamond .

The external diameter of a gold - sphere is 12 cm and it is made of a gold - plate of thichness 1 cm. If the weight of 1 cc gold be 19*5 gm and the price of 1 gm gold is ₹ 1280, then find the total price of the gold - sphere.

A hollow right circular cone of height h and of semivertical angle theta is placed with its base on a horizontal table. If the cone is filled with a liquid of density rho and the weight of the empty cone is equal to the weight of the liquid that it contains, find the thrust of the liquid on the base of the cone and the pressure exerted on the table.

A hollow glass sphere, containing atmospheric air, is weighed in air with the help of a balance. The sphere is then broken into pieces and the broken pieces are weighed again in air. Will there be any difference in the two weights? (Assume that the air pressure inside the sphere was equal to the external atmospheric pressure)

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