In the adjoining figure `/_ABC=90^@` and `BD` is perpendicular to `AC` express `(ADxxDC)` in terms of `BD`

In triangle ABC, AB=AC and BD is perpendicular to AC. Prove that : BD^(2)-CD^(2)=2CDxxAD

In the adjoining figure, chord AB ~= chord CD . Prove that arc AC ~= BD

In the adjoining figure, AB~=CD . Prove that arc AC ~=arc BD

In the given figure, DeltaABC is a right angled Deltawith /_B= 90^(@) and BD is perpendicular to AC. Prove that DeltaADB ~ DeltaABC

In the adjoining figure, O is centre of the circle chords AC and BD are perpendicular to each other, angle OAB = a and angle DBC = b . Show that a= b

In DeltaABC,angleC=90^(@) and CD is perpendicular to AB at D. If (AD)/(BD)=sqrtk , then (AC)/(BC)=?

ABC is a right triangle with right angle at B, AC = 2. BC = 1 and BD is perpendicular to AC. The area of the rectangle with BD as one of its diagonal is

In then the adjoining figure,/_B=70^(@),/_C=30^(@),BD and CD are the angular bisectors of /_ABC and /_ACD then value of /_BOC