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Statement I : The only circle having rad...

Statement I : The only circle having radius `sqrt(10)` and a diameter along line `2x+ y=5` is `x^2+y^2-6x+2y=0` Statement II : `2x + y = 5` is a normal to the circle `x^2 + y^2-6x + 2y = 0`.

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Statement 1: The only circle having radius sqrt10 and a diameter along line 2x+ y= 5 is x^(2) +y^(2) -6x +2y =0 Statement 2: 2x+y = 5 is a normal to the circle x^(2) + y^(2) -6x +2y=0

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Show that the line 5x + 12y - 4 = 0 touches the circle x^(2)+ y^(2) -6x + 4y + 12 = 0