Show that `|[1+a,1,1],[1,1+b,1],[1,1,1+c]|=abc(1+1/a+1/b+1/c)=abc+bc+ca+ab`

Answer the foll. Question : 2.show that |[1+a,1,1],[1,1+b,1],[1,1,1+c]| = abc(1+1/a+1/b+1/c) , (abc != 0)

Using properties of determinants show that abs[[1+a,1,1],[1,1+b,1],[1,1,1+c]]=abc(1+1/a+1/b+1/c)

det[[ Show that ,1+a,1,11,1+b,11,1,1+c]]=abc(1+(1)/(a)+(1)/(b)+(1)/(c))=abc+bc+ca+ab

Prove that |{:(1+a,1,1),(1,1+b,1),(1,1,1+c):}|=abc(1+1/a+1/b+1/c)or(abc+bc+ca+ab)

det[[ Prove that ,1+a,1,11,a+b,11,1,1+c]]=abc(a+(1)/(a)+(1)/(b)+(1)/(c))=abc+bc+ca+ab

Show that Determinant of [[1+a,1,1],[1,1+b,1],[1,1,1+c]] = abc (1+1/a+1/b+1/c)

|[1,a,bc] , [1,b,ca] , [1,c,ab]|=

Prove that: |1+a1111+b1111+c|=abc(1+(1)/(a)+(1)/(b)+(1)/(c))=abc+bc+ca+ab

Using properties of determinant show that : |(1+a,1,1),(1,1+b,1),(1,1,1+c)|=abc+ab+bc+ca

Prove that {:|(1+a,1,1),(1,1+b,1),(1,1,1+c)|=abc+bc+ca+ab