If the coordinates of the points A,B,C be `(-1,5),(0,0)` and `(2,2)` respectively, and D be the middle point of BC, then the equation of the perpendicular drawn from B to the line AD is

Let the coordinates of the points A, B, C be (1,8,4), (0,-11,4) and (2,-3,1) respectively. What are the coordinates of the point D which is the foot of the perpendicular from A on BC ?

Let the coordinates of the points A, B, C be (1,8,4), (0,-11,4) and (2,-3,1) respectively. What are the coordinates of the point D which is the foot of the perpendicular from A on BC?

The coordinates of the points A, B, C, D are (2, a), (3,5), (3,4) and (0, 6) respectively. If the lines AC and BD be perpendicular, then a = ?

The coordinates of the foot of the perpendicular drawn from the point (3,4) on the line 2x +y-7 =0 are

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

If A(3, -1, 11), B(0, 2, 3), C(4, 8, 11) are three points, then the foot of the perpendicular drawn from the point A to the line joining the points B and C is

In a triangle,ABC,the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinates of the points A and B are (1,-1)&(3,1) respectively,then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be