If z = `(3+isintheta)/(4-icostheta)` is purely real and `theta in (pi/2,pi)` ,then `arg(sintheta + i costheta)` is -

(costheta + isintheta)^4/(sintheta + icostheta)^5 is equal to.

(costheta + isintheta)^4/(sintheta + icostheta)^5 is equal to.

(costheta + isintheta)^4/(sintheta + icostheta)^5 is equal to.

If (3+2i sintheta)/(1-2i sintheta) is a real number and 0lt theta lt 2pi , then theta is a. pi \ b. pi/2 \ c. pi/3 \ d. pi/6

If (3+2i sintheta)/(1-2i sintheta) is a real number and 0lt theta lt 2pi , then theta is a. pi \ b. pi/2 \ c. pi/3 \ d. pi/6

If z is purely real; then arg(z)=0 or pi

If frac{3+isintheta}{4-icostheta}, theta in [0,2pi] , is a real number, then an argument of sintheta+icostheta is

Find real theta in (-pi,pi) so that (3+2isintheta)/(1-2isintheta) is purely real .

Let z=(costheta+isintheta)/(costheta-isintheta), pi/4 lt theta lt pi/2 . Then arg(z) =

Find real theta such that (3+2isintheta)/(1-2isintheta) is purely real.