The equation of the plane passing through the point `(1,1,1)` and perpendicular to the planes `2x+y-2z=5` and `3x-6y-2z=7` is

The equation of the plane passing through the point 1,1,1) and perpendicular to the planes 2x+y-2z=5a n d3x-6y-2z=7, is 14 x+2y+15 z=3 14 x+2y-15 z=1 14 x+2y+15 z=31 14 x-2y+15 z=27

The equation of the plane passing through the point (1,2,-3) and perpendicular to the planes 3x+y-2z=5 and 2x-5y-z=7 ,is

The equation of the plane passing through the point (1,2,-3) and perpendicular to the planes 3x+y-2z=5 and 2x-5y-z=7 is

The equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes x+2y+2z=5 and 3x+3y+2z=8 is -

The equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes x+2y+2z=5 and 3x+3y+2z=8 is -

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

Obtain the equation of the plane passing through the point (1,-3,-2) and perpendicular to the plane x+2y+2z=5 and 3x+3y+2z=8 .

Find the equation of the plane passing through the point (-1,3,2) and perpendicular to the planes x+2y+2z=5 and 3x+3y+2z=8 .