Home
Class 12
PHYSICS
An oil film (n = 1.45) floating on water...

An oil film `(n = 1.45)` floating on water is illuminated by white light at normal incidence. The film is 280 nm thick. Find (a) the color or the light in the visible specturm most strongly reflected and (b) the color of the light in the specturm most strongly transmitted. Explain your reasoning.

Promotional Banner

Similar Questions

Explore conceptually related problems

Oil floating on water looks cloured due to interference of light. What should be the approximate thickness of the film for such effects to be visible ?

Oil floating on water looks cloured due to interference of light. What should be the approximate thickness of the film for such effects to be visible ?

A parallel beam of white light is incident normally on a water film 1.0 x 10^-4 cm thick. Find the wavelength in the visible range (400 nm-700 nm) which are strongly transmitted by the film Refractive index of water = 1.33.

A parallel beam of white light is incident normally on a water film 1.0 x 10^-4 cm thick. Find the wavelength in the visible range (400 nm-700 nm) which are strongly transmitted by the film Refractive index of water = 1.33.

A parallel beam of white light is incident normally on a water film 1.0 x 10^-4 cm thick. Find the wavelength in the visible range (400 nm-700 nm) which are strongly transmitted by the film Refractive index of water = 1.33.

When white light is incident normally an oil film of thickness 10^-4 cm and refractive index. 1.4 then the wavelength which will not be seen in the reflected system of light is

When white light is incident normally an oil film of thickness 10^-4 cm and refractive index. 1.4 then the wavelength which will not be seen in the reflected system of light is

A 4.0 xx 10^(2) nm thick film of kerosene (n = 1.2) is floating on water. White light is normally incident on the film. What is the visible wavelength in air that has a maximum intensity after the light is reflected? Note: The visible wavelength range is 380 nm to 750 nm.