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Find the dimensions of physical quantity...

Find the dimensions of physical quantity `X` in the equation
`"Force" = ( X) /("Density")`.

Text Solution

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`[ X] = ["Force"] xx ["Density"] = [MLT^(-2)] xx [ ML^(-3)] = [ M^(2) L^(-2) T^(-2)]`
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Knowledge Check

  • The dimensions of physical quantity X in the equation force = X/(sqrt("Density")) is given by :

    A
    `M^1 L^4 T^(-2)`
    B
    `M^2 L^(-2) T^(-1)`
    C
    `M^(3//2) L^(-1//2) T^(-2)`
    D
    `M^(1) L^(-2) T^(-1)`

  • The dimension of the physical quantity alpha in the equation. E = V alpha . Where E is the energy and V is voulume has same dimesion as of

    A
    Impulse
    B
    Power
    C
    Linear Momentum
    D
    Pressure

  • Pairs of physical quantities having same dimensions are

    A
    Reynolds number and strain
    B
    Torque and force
    C
    Curie and frequency
    D
    Gravitational potential and latent heat

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    When dimensions of a given physical quantity are given,the physical quantity is unique .

    The pairs of physical quantities that have the same dimensions are :

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