Given `R_(1) = 5.0 +- 0.2 Omega, and R_(2) = 10.0 +- 0.1 Omega`. What is the total resistance in parallel with possible `%` error?

Explanation

To find the total resistance in parallel for the given resistances \( R_1 \) and \( R_2 \) along with the possible percentage error, we can follow these steps:

### Step 1: Identify the values of the resistances and their uncertainties
- Given:
- \( R_1 = 5.0 \, \Omega \) with an uncertainty of \( \Delta R_1 = 0.2 \, \Omega \)
- \( R_2 = 10.0 \, \Omega \) with an uncertainty of \( \Delta R_2 = 0.1 \, \Omega \)

### Step 2: Calculate the total resistance in parallel
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