The length of a cylinder is measured with a meter rod having least count `0.1 cm`. Its diameter is measured with Vernier calipers having least count `0.01 cm`. Given that length is `5.0 cm` and radius is ` 2 cm`. Find the percentage error in the calculated value of the volume.

Explanation

Volume of cylinder `V = pi r^(2) l`
Percentage error in volume
`( Delta V)/(V) xx 100 = ( 2Delta r)/( R ) xx 100 + ( Delta l )/( l) xx 100`
` = (2 xx ( 0.01)/( 2.0) xx 100 + (0.1)/(5.0) xx 100)`
`= ( 1+2)% = 3%`