The length and breadth of a rectangle are `( 5.7 +- 0.1 ) cm and ( 3.4 +- 0.2 ) cm`, respectively calculate the area of rectangle with error limits.

Answer

`( 19 +- 1.5) cm^(2)`

Explanation

`A = l b = 5.7 xx 3.4 = 19.38 cm^(2) ~ 19 cm^(2)`
( two significant figures)
`(Delta A )/( A) = (Delta l )/( l) + ( Delta b)/(b) rArr Delta A = ((0.1)/(5.7) + (0.2)/(3.4)) ( 19.38)`
`Delta A = 1.48 = 1.48 ~ 1.5`
( two significant figures)
So area `= ( 19 +- 1.5) cm^(2)`