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Two resistances R(1) = 100 +- 3 Omega an...

Two resistances `R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega` are connected in series . Find the equivalent resistance of the series combination.

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The correct Answer is:
`300+- 7 ohm`
The equivalent resistance
`R = R_(1) + R_(2) = (100 +- 3) ohm + ( 200 +- 4) ohm`
` = 300 +- 7 ohm`
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