A capacitor of capacitance `C = 2.0 +- 0.1 mu F` is charged to a voltage `V = 20+- 0.2 V`. What will be the charge `Q` on the capacitor ? Use `Q = CV`.

Answer

`40 +- 2.4xx10^(-6)` coulomb

Explanation

If we omit all errors , then
`Q = CV = 2.0 xx 10^(-6) xx 20` coulomb `= 40 xx 10^(-6) coulomb`
Error in `C = 0.1 part in 2 = 1 part in 20 = 5%`
Error in `V = 0.2 part in 20 = 2 part in 200 = 1 part in 100 = 1%`
Error in `Q = 5% + 1% = 6%`
Charge , `Q = 40 xx 10^(-6) +- 6%` coulomb
`= 40 +- 2.4 xx 10^(-6)` coulomb