Write the dimensions of `a//b` in the relation `P = ( a - t^(2))/( bx)` , where `P` is the pressure , `x` is the distance , and `t` is the time .

Options

A. `M^(-1) L^(0)T^(-2)`
B. `M L^(0)T^(-2)`
C. `M L^(0)T^(2)`
D. `M LT^(-2)`

Answer

B

Explanation

Here `a` has the same dimensions as `t^(2)`.
` a = [ T^(2)] , b = (T^(2))/(P.x) = (T^(2))/(ML^(-1) T^(-2) L^(1)) = (T^(4))/( M) = [ M^(-1) T^(4)]`
Now `(a)/(b) = (T^(2)) /(M^(-1)T^(4)) = ML^(0)T^(-2)`