The length of a strip measured with a meter rod is 10.0cm. Its width measured with a venier calipers is 1.00cm. The least count of the meter rod is 0.1 cm and that of vernier calipers 0.01cm. What will be error in its area?

Options

A. `+- 0.01 cm^(2)`
B. `+- 0.1 cm^(2)`
C. `+- 0.11 cm^(2)`
D. `+- 0.2 cm^(2)`

Answer

D

Explanation

`Delta A = (( Delta l)/( l) + ( Delta b)/( b)) A = +- (( 0.1)/( 10.0) + ( 0.01)/( 1.00)) xx ( 10.0 xx 1.00) cm^(2)`
` = +- 0.02 xx 10 = +- 0.2 cm^(2)`