Plot the line `-3x-5y=15`.

Explanation

Method 1: Given `5y=-3x-15`
Using `y=mx+c, y=-3/5x-3`
Here the slope is negative, i.e., the line makes an angle greater than `90^(@)` with the x-axis. As intercept is negative, it indicates that the line will cut the y-axis on its negative side (figure)

when `x=0`, `y=-3`.
When `y=0`, `x=-5`.
Method 2: Using `x/a+y/b=1`,
`(-3x)/(15)-(5y)/(15)=1implies(x)/((-5))+(y)/((-3))=1`