If `y=3x^2+2x`, then find `dy//dx`.

Options

A. 6x-2
B. 6x
C. 6x+1
D. `6x+2`

Answer

D

Explanation

`(dy)/(dx)=(d)/(dx)[3x^2]+(d)/(dx)[2x]`
(Using the linearity property of differentiation)
`(dy)/(dx)=3(d[x^2])/(dx)+2(d[x])/(dx)` (Separating the constant coefficients)
`=3xx2x^(2-1)+2xx1x^(1-1)=6x+2`
`("Using" (d[x^(n)])/(dx)=nx^(n-1))`