Home
Class 11
PHYSICS
Calculate the area enclosed under the cu...

Calculate the area enclosed under the curve `f(x)=x^2` between the limits `x=2` and `x=3` (figure)

A

6.333

B

9.233

C

18.55

D

0

Text Solution

Verified by Experts

The correct Answer is:
A

`underset2overset3intf(x)dx=underset2overset3intx^2dx`
`=(x^(3))/(3)|_2^3`
`=((3)^3)/(3)-(2)^3/3=19/3=6.333`
Promotional Banner

Topper's Solved these Questions

  • BASIC MATHEMATICS

    CENGAGE PHYSICS|Exercise Solved Examples|9 Videos
  • BASIC MATHEMATICS

    CENGAGE PHYSICS|Exercise Exercise 2.1|2 Videos
  • ARCHIVES 2 VOLUME 6

    CENGAGE PHYSICS|Exercise Integer|4 Videos
  • CALORIMETRY

    CENGAGE PHYSICS|Exercise Solved Example|13 Videos

Similar Questions

Explore conceptually related problems

Calculate the area under the curve y=2sqrtx included between the lines x = 0 and x = 1.

Calculate the area under the curve y=2sqrtx included between the lines x = 0 and x = 1.

The area enclosed by the curve y^(2)+x^(4)=x^(2) is

Find the area under the curve y=(x^(2)+2)^(2)+2x between the ordinates x=0 and x=2

What is the area enclosed between the curve y^(2)=12x and the lines x=0 and y=6?

Determine the area enclosed by the curve y=x^3 , and the lines y=0,x=2 and x = 4.

Find the area under the curve f(x)=2x from[0,2].

Compute the area enclosed by the curve y^(2)= (1-x^(2))^(3)

Find the area under the curve f(x)=x^(3/2) from[0,2]

What is the area enclosed by the curve 2x^(2)+y^(2)=1 ?

CENGAGE PHYSICS-BASIC MATHEMATICS-Exercise 2.6
  1. Calculate the area enclosed under the curve f(x)=x^2 between the limit...

    Text Solution

    |

  2. The displacement of a particle is given by y=(6t^2+3t+4)m, where t is ...

    Text Solution

    |

  3. The velocity of a particle is given by v=12+3(t+7t^2). What is the acc...

    Text Solution

    |

  4. A particle starts from origin with uniform acceleration. Its displacem...

    Text Solution

    |

  5. The acceleration of a particle is given by a=t^3-3t^2+5, where a is in...

    Text Solution

    |

  6. A particle starts moving along the x-axis from t=0, its position varyi...

    Text Solution

    |

  7. A particle moves along the x-axis obeying the equation x=t(t-1)(t-2), ...

    Text Solution

    |

  8. The speed of a car increases uniformly from zero to 10ms^-1 in 2s and ...

    Text Solution

    |

  9. A car accelerates from rest with 2ms^-2 for 2s and then decelerates co...

    Text Solution

    |

  10. A stationary particle of mass m=1.5kg is acted upon by a variable forc...

    Text Solution

    |

  11. The displacement of a body at any time t after starting is given by s=...

    Text Solution

    |

  12. A particle moves along a staight line such that its displacement at an...

    Text Solution

    |

  13. The displacement x of a particle moving in one dimension under the act...

    Text Solution

    |

  14. The position x of a particle varies with time t according to the relat...

    Text Solution

    |

  15. The displacement of a particle along the x-axis is given by x=3+8t+7t^...

    Text Solution

    |

  16. The acceleration a in ms^-2 of a particle is given by a=3t^2+2t+2, whe...

    Text Solution

    |

  17. The displacement x of a particle along the x-axis at time t is given b...

    Text Solution

    |

  18. A particle moves along a straight line such that its displacement s at...

    Text Solution

    |

  19. The acceleration of a bus is given by ax(t)=at, where a=1.2ms^-2. a....

    Text Solution

    |

  20. The acceleration of a motorcycle is given by ax(t)=At-Bt^2, where A=1....

    Text Solution

    |

  21. The acceleration of a particle varies with time t seconds according to...

    Text Solution

    |