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Using the method of integration show tha...

Using the method of integration show that the area of triangle of base b and altitude h is `1/2bh`.

Text Solution

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Let ABC be the triangle with base `BC=b` and altitude `AM=h`.
Let us consider a thin strip DE on the triangle of thickness `dx`, at a distance x from the vertex A, parallel to the base BC.

If y be the length of the strip DE, then form similar triangles
ABC and ABC, we have `y/x=b/h`.
`impliesy=(bx)/(h)`
Therefore, the area of the rectangular strip DE is given by
`dA=ydx=(bxdx)/(h)`
The complete area of the triangle can be obtained by summing up (integration) the area of individual strips such as DE.
`A=sumdA=underset0oversethint(bxdx)/(h)=b/h[x/2]^h=(b)/(2h)(h^2-0)=1/2bh`
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