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If a particle starts moving along x-axis...

If a particle starts moving along x-axis from the origin with initial velocity `u=1ms^-1` and acceleration `a=2ms^-2`, the relationship between displacement and time is
`x=ut+1/2at^2=1xxt+1/2xx2xxt^2=t+r^2`
Draw the displacement (x)-time (t) graph.

Text Solution

Verified by Experts

`x=t+t^2`, `a=1`, `b=1`, `c=0`
Vertex: `t=-(b)/(2a)=-(1)/(2xx1)=-1/2`
At `t=-1/2`, `x=-1/4`

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